Question

(3m³+4n²)(2m+3n²+12mn²) find the product ​

Answer 1

Step-by-step explanation:

=3*m^3(2m + 3*n^2 + 12*m*n^2) + 4*n^2 (2m + 3*n^2 + 12*m*n^2)

=6*m^4 + 9*m^3*n^2 + 36*m^4*n^2 + 8*m*n^2 + 12*n^4 + 48*m*n^4

U can also take common from above if you want. It's up to you