3men can complete a piece of work in 6 days. two days after they started the work, 3 more men joined them. how many days will they take to complete the remaining work?
Answers
Answered by
0
3men in 6days
1man in 1day work done= 1/18
work remains= 1- 1/9= 8/9
time taken by 1man = 8/9 ÷ 1/18=16
by 6 man 16/6=2 ⅔
1man in 1day work done= 1/18
work remains= 1- 1/9= 8/9
time taken by 1man = 8/9 ÷ 1/18=16
by 6 man 16/6=2 ⅔
Similar questions