(3mn-4pq)-(2mn-5pq)
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Step-by-step explanation:
First draw a line segment AB = 6 cm. (ii) Draw a ray AX with pencil and compass such that ∠BAX = 90°. Draw an arc of 4 cm with point A which intersects AX at D. (iii) Similarly, draw ray BY such that ∠ABY = 90°. Draw an arc of 4 cm with point B which intersects BY at C. (iv) Join CD. Thus ABCD is the required rectangle.Read more on Sarthaks.com - https://www.sarthaks.com/815409/construct-a-rectangle-whose-adjacent-sides-are-6-cm-and-4-cm
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