Question

3n + 2\3 =2n+1 solve the following equation ​

Answer 1

Answer:

Given :

$\sf{3n+\dfrac{2}{3}=2n+1}$

To find :

$\textsf{The value of n in the equation. }$

Concept :

Just solve the 3n and 2n . And solve the ⅔ and 1 . After solving both the answer will come .

Solution :

$\sf{\implies{3n+\dfrac{2}{3}=2n+1}}$

$\sf{\implies{3n-2n=1-\dfrac{2}{3}}}$

$\sf{\implies{n=\dfrac{1}{1}-\dfrac{2}{3}}}$

So , L.C.M of 1 and 3 is 3 .

$\sf{\implies{n=\dfrac{3-2}{3}}}$

$\sf{\implies{n=\dfrac{1}{3}}}$

$\sf{So,value\:the\:of\:n\:is\:\dfrac{1}{3}}$

Answer :

$\textsf{Value of n of the equation= }$$\sf{\dfrac{1}{3}}$

Answer 2

Answer:

$3n + \frac{2}{3} = 2n + 1 \\ \\ = > \frac{9n + 2}{3} = 2n + 1 \\ \\ = > 9n + 2 = 3(2n + 1) \\ \\ = > 9n + 2 = 6n + 3 \\ \\ = > 9n - 6n = 3 - 2 \\ \\ = > 3n = 1 \\ \\ = > n = \frac{1}{3}$