Math, asked by yaseenaman4451, 6 months ago

3n× 4m cannot end with the digit 0 or 5

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Answered by ns7817295

0

Answer:

$3n \times 4m \: cannot \: end \: with \: the \: digit \: 0 \: or \: 5 \: because \: when \: multiply \: 3 \: and \: 4 \: we \: get \: 12 \: but \: if \: a \: number \: want \: to \: end \: with \: 0 \: it \: should \: be \: divisible \: by \: 2 \: and \: 5 \: and \: a \: number \: end \: with \: 5 \: it \: must \: be \: divisible \: by \: 5and \: not \: by \: 2$

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