-3n square + 51n-156 = 0
middle term spliting
solve fast ,
tomorrow is my exam
urgent,
Answers
Answered by
22
Heya !!!
This is your answer.
Given equation :-
-3n^2 + 51n - 156 = 0.
We will do two steps to make it simple and easy to solve :-
First ....
Multiply the whole equation by (-), we get
3n^2 - 51n + 156 = 0.
Now take out 3, as it is common in all.
n^2 - 17n + 52 = 0
Now we have to find two numbers a and b such that a+b = -17 and ab = 52.
By looking at the prime factors of 52..
52 = 2 X 2 X 13.
We get a and b as -4 and -13.
Therefore......
n^2 - 17n + 52 = 0.
n^2 - 13n - 4n + 52 = 0
n (n-13) - 4 (n-13) = 0.
(n-4)(n-13) = 0.
n - 4 = 0 or n - 13 = 0
n = 4 or n = 13.
Hence the two zeroes are 4 and 13.
Hope it helps
This is your answer.
Given equation :-
-3n^2 + 51n - 156 = 0.
We will do two steps to make it simple and easy to solve :-
First ....
Multiply the whole equation by (-), we get
3n^2 - 51n + 156 = 0.
Now take out 3, as it is common in all.
n^2 - 17n + 52 = 0
Now we have to find two numbers a and b such that a+b = -17 and ab = 52.
By looking at the prime factors of 52..
52 = 2 X 2 X 13.
We get a and b as -4 and -13.
Therefore......
n^2 - 17n + 52 = 0.
n^2 - 13n - 4n + 52 = 0
n (n-13) - 4 (n-13) = 0.
(n-4)(n-13) = 0.
n - 4 = 0 or n - 13 = 0
n = 4 or n = 13.
Hence the two zeroes are 4 and 13.
Hope it helps
RehanAhmadXLX:
If it helps mark as brainliest
Answered by
1
Answer:
your answer is n=4 or n=13
hope it helps you
thank you
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