Question

3n square -603n plus 16200;find the value of n

Answer 1

Given-:

3n² - 603n + 16200 = 0

We know that-:

This is in the form of a quadratic equation and as our quadratic equation information a quadratic equation has its highest degree as two.

There are two methods to solve quadratic equation-:

(i) middle term factorisation method

(ii) Formula n = [-b ± (b² - 4ac)¹/²]/2a

So-:

=> 3n² - 603n + 16200 = 0

On using formula

From Quadratic equation we have-:

a = 3,

b = -603 &

c = 16200

=> n=[-(-603) ± {(603)² - 4*3*16200}¹/²]/2*3

=> n = [603 ± (363609 - 194400)¹/²]/6

=> n = [ 603 ± (169, 209)¹/²]/6

=> n = [603 ± 411.35]/6

On taking postive sign-:

=> n = 603 + 411.35/6

=> n =169.05

On taking negative sign-:

=> n = 603 - 411.35/6

=> n =31.94

Therefore-:

The +ve value of n is 169.05 and the negative value is 31.94.

Answer 2

Step-by-step explanation:

Solution is in the attachment