Question

3n2-53n+232 by factorisation pls fast

Answer 1

Answer:

$Factors \: of \: 3n^{2}-53n+232 = (3n-29)(n-8)$

Step-by-step explanation:

$Given \: quadratic \: expression :\\3n^{2}-53n+232$

/* Splitting the middle term,we get

$= 3n^{2}-29n-24n+232\\=3n^{2}-29n -8\times 3n + 8 \times 29 \\= n(3n-29)-8(3n-29)\\=(3n-29)(n-8)$

Therefore.,

$Factors \: of \: 3n^{2}-53n+232 = (3n-29)(n-8)$

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Answer 2

Answer:

3n^2- 24n-29n+232=0

3n(n-8)-29(n-8)=0

(3n-29) ,(n-8)=0

3n= 29 ,n=8

n=29/3,n=8.