Question

3numbers of AP whose aim is 15&sumof the square of the extreme is 58 find 3nbers of AP

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Answer 1

Answer:

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Answer 2

Answer:

3,5,7

Step-by-step explanation:

sum of the three numbers is 15

let the numbers in AP are a-d,a,a+d

sum of them

a-d+a+a+d=15

3a=15

a=5

given the sum of the square of the extreme is 58

$(a-d)^{2}+(a+d)^{2}$ =58

$a^{2} +d^{2} +2ad+a^{2} +d^{2} -2ad$=58

2($a^{2} +d^{2}$)=58

($a^{2} +d^{2}$)=29

a=5

25+$d^{2}$=29

$d^{2}$=4

d=+2,-2

the numbers are 3,5,7