Question

(3p^2 - 14pq + 2r) - (14pq + 3p^2 + 2r^2) is a-
(i) monomania
(ii) binomial
(iii) trinomial
(iv) none

And please explain how??? ​

Answer 1

Answer :-

Trinomial

Step-by-step explanation:

We have ,

= ( 3p² - 14pq + 2r ) - ( 14pq + 3p² + 2r² )

= ( 3p² - 14pq + 2r - 14pq - 3p² - 2r² )

= ( -28pq + 2r - 2r² )

= -2r² + 2r - 28pq.

Hence the given expression is a trinomial .

Here ,

=> Monomial :- An expression containing only one term is called a monomial .

=> Binomial :- An expression containing only one term is called a biomial .

=> Trinomial :- An expression containing only three term is called a monomial .

Answer 2

Answer:

nothing

Step-by-step explanation: