Math, asked by THEOP, 8 months ago

(3p + 2) – 5(6p -1) = 2(p – 8) - 6(7p - 4)​

Answers

Answered by aryan1234243
6

Step-by-step explanation:

(3p+2)-30p+5=2p-16-42p+24

3p+2-30p+5=2p-16-42p+24

-27p+7=-40p+8

-27p+7+40p-8=0

13p-1=0

p=1/13

Answered by BRAINLYADDICTOR
89

Answer:

➡(3p + 2) – 5(6p -1) = 2(p – 8) - 6(7p - 4)

️➡️3p+2-30p+5=2p-16-42p+24

➡-27p+7=-40p+8

️➡️-27p+40p=8-7

➡13p=1

️➡️P=1/13

➡️(3p + 2) – 5(6p -1) = 2(p – 8) - 6(7p - 4)

Sub, p=1/13 in above equation

➡️(3(1/13)+2)-5(6(1/13-1)=2(1/13-8)-6(7(1/13)-4)

➡️3/13+26/13-30/13+65/13=2/13-208/13-42/13+312/13

➡️3+26+65-30/13=2-208-42+312/13

➡️94-30/13=314-250/13

➡️64/13=64/13

➡64(13)=64(13)

️➡️832=832

➡️1=1

Hence proved..

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