Question

3p^2+7p+1=0 solve by comleting square method

Answer 1

HEY MATE!

HERE IS YOUR ANSWER:

3p^2+7p+1=0

3p^2+7p=-1

3p^2/3+7p/3=-1/3

p^2+7p/3=-1/3

p^2+7p/3+(1/2×7/3)^2=-1/3(1/2×7/3)^2

p^2+7p/3+(7/6)^2=-1/3(7/6)^2

(p+7/6)^2=-1/3×49/36

(p+7/6)^2=-49/108

As root of negative is not possible so, the equation does not have real roots.

Hope it helped ^_^

Answer 2

☆ Answer ☆

$3 {p}^{2} + 4 = - 7p$

$3 {p}^{2} + 7p + 4 = 0$

${p}^{2} \: \: \frac{7}{3} p \: + \frac{4}{3} = 0$

Dividing both by sides 3

$coefficient \: of \: p \: is \: \frac{7}{3}$

$now ( \: { \frac{1}{2} \times \frac{7}{3}) }^{2} = ( { \frac{7}{6}) }^{2} = \frac{49}{36}$

Now adding both sides by

$\frac{49}{36}$

${p}^{2} \frac{7}{3}p + \frac{49}{36} = - \frac{4}{3} + \frac{49}{36}$

$(p + { \frac{7}{6}) }^{2} = \frac{ - 48 + 49}{36}$

$(p + { \frac{7}{6}) }^{2} = \frac{1}{36}$

$(p + \frac{7}{6}) = \frac{ + 1}{6}$

$p = \frac{ + 1}{6} - \frac{7}{6}$

$p = \frac{1}{6} - \frac{7}{6} \: or \: p = \frac{ - 1}{6} - \frac{7}{6}$

$p = - 1 \: or \: p \: = \frac{ - 4}{3}$

hope this will help you. ..