Question

3p*2+q*2=2p*2+2q*2+2pqcosa​

Answer 1

Answer:

I don't know

Step-by-step explanation:

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Answer 2

Answer:

0

Step-by-step explanation:

Given p&q = p^2 + q^2 - 2pq (I am assuming the sign before 2pq is '-')

We want the value of q such that p&q = p^2

i.e. p2+q2−2pq=p2p2+q2−2pq=p2

This means that q2−2pqq2−2pq should be 0 so that left side becomes equal to right side.

If q = 0, both q^2 and 2pq will become 0.

or you can do it algebraically too: q2−2pq=0q2−2pq=0

q(q−2p)=0q(q−2p)=0

So if q = 0 or if q = 2p, p&q will be equal to p2p2.

We have q = 0 in the options hence answer (C)