Question

(3p^2 qr^-2 / 2p^-1 q^3)^2 ÷ (2p^3 r)^-1

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Answer 1

Answer:

1:Equation at the end of step 1

(ha•t (—————————————————) ÷ ((2•(p-1))•(q3))•2)•((2p3•r)-1) (3•(p((2qr)^-2)))

STEP 2 :

Equation at the end of step2:

(ha•t (—————————————————) ÷ (2p(-1)•q3)•2)•(2)(-1)p(-3)r(-1) (3•(p((2qr)^-2)))

STEP3:

Equation at the end of step3:

(ha•t (————————————————————————) ÷ 2p(-1)q3•2)•(2)(-1)p(-3)r(-1) (3•(p(2)(-2)q(-2)r(-2)))

Answer 2

Answer:

9P^9/2q^4r^3

Step-by-step explanation:

step 1

9p^4q^2r^-4/4p^-2q^6*1/2^-1p^-3r^-1

step 2

9p^6/4q^4r^4*2p^3r

step 3

9p^9/2q^4r^3