(3p-2q+r )+( p+2q-3r)-(2p-2q+4r) solve the problem
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(3p-2q+r)+(p+2q-3r)-(2p-2q+4r)
= (4p-0-2r)-(2p-2q+4r)
= 2p-2q+2r
= 2(p-q+r) //Ans.
= (4p-0-2r)-(2p-2q+4r)
= 2p-2q+2r
= 2(p-q+r) //Ans.
Preetigupta1:
what I know
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Heya ☺
(3p - 2q + r) + (p + 2q - 3r) - (2p - 2q + 4r)
= 3p - 2q + r + p + 2q - 3r - 2p + 2q - 4r
= 3p + p - 2p - 2q + 2q + 2q + r - 3r - 4r
= 4p - 2p + 2q - 2r - 4r
= 2p + 2q - 6r
Thanks
(3p - 2q + r) + (p + 2q - 3r) - (2p - 2q + 4r)
= 3p - 2q + r + p + 2q - 3r - 2p + 2q - 4r
= 3p + p - 2p - 2q + 2q + 2q + r - 3r - 4r
= 4p - 2p + 2q - 2r - 4r
= 2p + 2q - 6r
Thanks
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