Question

(3p+4)^2 solve using identity​

Answer 1

Answer:

(3p+4)^2. (a+b)^2=a^2+b^2+2ab)

(3p)^2+4^2+2×3p×4

9p^2+16+24p

Answer 2

$(3p + 4)^{2} \\ \\ as \: we \: know \: \\ (a + b) ^{2} = a {}^{2} + b {}^{2} + 2ab \: \\ here \: a = 3p \: . \: b = 4 \\ \\ = (3p) {}^{2} + (4) {}^{2} + 2 \times 4 \times 3p \\ = 9p {}^{2} + 16 + 36p \\ \\ \\ this \: is \: your \: answer \: \\ \\ please \: mark \: me \: as \: brainlist \:$