(3p-4q)(9p^2+16q^2+12pq) find using suitable identity
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Answer:
27p^3-64q^3
Step-by-step explanation:
(3p-4q)(9p^2+16q^2+12pq)
Lets say 3p=a and 4q=b, then we have:
(3p-4q)(9p^2+16q^2+12pq)=
(a-b)(a^2+b^2+ab)=a^3-b^3
Converting back:
a^3-b^3=(3p)^3-(4q)^3=27p^3-64q^3
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