Question

3p+7p+4 =0 using square method formula

Answer 1

Step-by-step explanation:

doing like this ok hope helpful to you

Answer 2

Answer:

hey mate...

this equation is wrong...

this is right..

3p^2 + 7p + 4 = 0

divide by 3

= p^2 + 7p/3 = - 4/3

= as (a+b) ^2 = a^2 + 2*a*b + b^2

= p^2 + 2*p*7/6 + (7/6) ^2 = -4/3 + (7/6)^2

= (p+7/6) ^2 = -4/3 + 49/36

= (p+7/6) ^2 = 1/36

= (p+7/6) ^2 = √(1/36)

= (p+7/6) ^2 = √1/6

= (p+7/6) ^2 = (√1/6) ^2

= (p+7/6) = +√1 /6

-

= p+7/6 = √1/6

= p = (√1 - 7 ) /6

= p+7/6 = -√1/6

= p = (-√1_7) /6

hope it helps you...

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