3p=sec and 3/p= tan find the value of p^2-1/p^2
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Here secA+tanA=p
Or, 1/cosA+sinA/cosA=p(since secA=1/cosA and tanA=sinA/cosA)
Or, (1+sinA)/cosA=p
Or, (1+sinA)^2/cos^2A=p^2(squaring both sides)
Or, (1+sinA)^2/(1-sin^2A)=p^2
Or, (1+sinA)^2/(1+sinA)(1-sinA)=p^2
Or, (1+sinA)/(1-sinA)=p^2
Or, (1+sinA+1-sinA)/(1+sinA-1+sinA)=(p^2+1)/p^2–1)(since a/b=c/d imply a+b/a-b=c+d/c-d)
Or, 2/2sinA=p^2+1/p^2–1
Or, 1/sinA=p^2+1/p^2–1
Or, cosecA=p^2+1/p^2–1
its correct answer plzz.... suport
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