Question

(3p²/2 + 2q²/3) × (2p² - 3q²)

Please solve the above question..​

Answer 1

Answer:

3p⁴ - ( 19 p²q² /6 ) -2q⁴

Step-by-step explanation:

(3p²/2 + 2q²/3) (2p² - 3q²)

=> (3p²/2 × 2p² ) + ( 3p²/2 ×(-3q²)) + (2q²/3 × 2p² ) + (2q²/3 × (-3q²))

=> 3p⁴ + (-9p²q²/2 ) + ( 4p²q²/3) - 2q⁴

=> 3p⁴ + [ p²q² { (-9/2) + (4/3) }] -2q⁴

=> 3p⁴ + [ p²q² { (-9×3 + 4×2) ÷ (2×3) }] -2q⁴

=> 3p⁴ + [ p²q² { (8-27) ÷ 6}] -2q⁴

=> 3p⁴ + [ p²q² { (-19) ÷ 6}] -2q⁴

=> 3p⁴ - ( 19 p²q² /6 ) -2q⁴

PLEASE MARK BRAINLIEST , IF U FOUND IT USEFUL

Answer 2

Step-by-step explanation:

(3/2 p^2 + 2/3 q^2 ) × (2p^2-3q2)

=(3×3p^2 + 2×2q^2)/6 × (2p^2-3q2) LCM of 2,3 is 6 =(9p^2 + 4q^2)/6 × (2p^2-3q2)

=(9p^2×(2p^2-3q^2) + 4q^2 × (2p^2-3q2))/6

=(18p^4 - 27p^2q^2 + 8p^2q^2 - 12q^4)/6

=(18p^4 -19p^2q^2-12q^4)/6

=3p^4 -(19p^2q^2)/6-2q^4