3p²+8p+5=0 solve by factorisation method.
Answers
Answer:
Factoring 3p2-8p+5
The first term is, 3p2 its coefficient is 3 .
The middle term is, -8p its coefficient is -8 .
The last term, "the constant", is +5
Step-1 : Multiply the coefficient of the first term by the constant 3 • 5 = 15
Step-2 : Find two factors of 15 whose sum equals the coefficient of the middle term, which is -8 .
-15 + -1 = -16
-5 + -3 = -8 That's it
Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -5 and -3
3p2 - 5p - 3p - 5
Step-4 : Add up the first 2 terms, pulling out like factors :
p • (3p-5)
Add up the last 2 terms, pulling out common factors :
1 • (3p-5)
Step-5 : Add up the four terms of step 4 :
(p-1) • (3p-5)
Which is the desired factorization
Step-by-step explanation:
hope it help u
Step-by-step explanation:
We Have :-
3p² + 8p + 5 = 0
To Find :-
Factors
Method Used :-
Factorisation method
Solution :-
3p² + 8p + 5 = 0
3p² + 3p + 5p + 5 = 0 ( 8p can be written as 8p = 3p + 5p )
3p ( p + 1 ) + 5 ( p + 1 ) = 0
( p + 1 ) ( 3p + 5 ) = 0
Either ( p + 1 ) = 0 or ( 3p + 5 ) = 0
Putting ( p + 1 ) = 0
p + 1 = 0
p = -1
Putting ( 3p + 5 ) = 0
3p + 5 = 0
3p = -5
p = -5/3