Math, asked by nksingh13279, 1 year ago

3p2q+5pq2+2pqr p=2,q=1,r=3

Answers

Answered by jahanulfat270
1

Answer:

the answer will be 34

Step-by-step explanation:

3p2q+5pq2+2pqr where, p=2 , q =1, and r=3

then,

=3(2)2.1+5.2.(1)2+2.2.1.3

=3.(4).1+10.(1)+4.1.3

=12+10+12

=34

Answered by mohanprakash1480
0

Step-by-step explanation:

= 3p2q. +5pq2+ 2pqr

= 3(2)2(1) +5(2)(1)2. +2(2)(1)(3)

= 6*2. +10*2 +12

= 12. +20. +12

= 44

Similar questions