Question

3pq-4pq+5,-10pq,15+9pq+7pq​

Answer 1

Answer:

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Step-by-step explanation:

addition of 3p²q²-4pq+5 , -10p²q²,15+9pq+7p²q²

=(3p²q²-4pq+5)+(-10p²q²)+15+9pq+6p²q²

= ( 3 - 10 + 6 )p²q² + ( -4 + 9 )pq+5+15

= -1p²q² + 5pq + 20

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Answer 2

Answer:-

Addition :-

$(3pq - 4pq + 5) + ( - 10pq) + (15 + 9pq + 7pq)$

$3pq - 4pq + 5 - 10pq + 15 + 9pq + 7pq$

$3pq - 4pq - 10pq+ 9pq + 7pq + 5 + 15$

$5pq + 20$

Subtraction :-

$(3pq - 4pq + 5) - ( - 10pq) - (15 + 9pq + 7pq)$

$3pq - 4pq + 5 + 10pq - 15 - 9pq - 7pq$

$3pq - 4pq + 10pq - 9pq - 7pq + 5 - 15$

$- 7pq - 10$