Math, asked by SreejithL, 4 months ago

3pqr-6p^2 q^2 r^2-15r^2​

Answers

Answered by farhaanaarif84
0

Answer:

The dividion is carried out as follows :

3pq

3pqr−6p

2

q

2

r

2

=

3pq

3pqr

3pq

6p

2

q

2

r

2

=

3⋅p⋅q

3⋅p⋅q⋅r

3⋅p⋅q

2⋅3⋅p⋅p⋅q⋅r⋅r

Cancelling out the common factors in numerator and denominator,

=r−2⋅p⋅q⋅r⋅r

=r−2pqr

2

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