Math, asked by ranimallesh46, 11 months ago

(3pqr-6p²q²r²)÷3pq factorise​

Answers

Answered by Anonymous
26

Answer:

\sf{r(1 - 2pqr)}

Step-by-step explanation:

Given : \sf{ {\dfrac{3pqr - 6p^2q^2r^2}{3pq}}}

On further solving, we get

\sf{ {\dfrac{3pq(r - 2pqr^2)}{3pq}}}

\sf{ {\dfrac{ {\cancel{3pq}} (r - 2pqr^2)}{ {\cancel{3pq}} }}}

\sf{r - 2pqr^2}

r(1 - 2pqr)

Answered by rainarakesh8715
2

Answer:

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