Question

(3q+7p²–2r³+4)–(4p²+2q–7r³–3)=​

Answer 1

Answer:

5r³ + 3p² + q + 7

Step-by-step explanation:

We have , ( 3q + 7p² – 2r³ + 4 ) – ( 4p² + 2q – 7r³ – 3 )

On opening brackets , we get

3q + 7p² –2r³ + 4 - 4p² - 2q + 7r³ + 3

= 7r³ –2r³ + 7p² - 4p² + 3q - 2q + 4 + 3

= 5r³ + 3p² + q + 7  

Answer 2

Answer:

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