(3r - 2k)' + (3r + 2k);
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Answered by
9
Answer:
By using Identity ⤵️
a²-b² = (a+b) (a-b)
(3r²-2k²) = (3r+2k)+(3r-2k)
Explanation:
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Answered by
25
( a - b ) ( a + b ) = a² + b²
Therefore,
(3r - 2k) + (3r + 2k) = 3r² + 2k²
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