Math, asked by arjun909, 9 months ago

(3r-4)^2-4(3r-4)-12​

Answers

Answered by ananthukrishnan456
1

Answer:

x = 2 + 4i/3 or x = 2 - 4i/3

Step-by-step explanation:

(3r - 4)^2 - 4(3r - 12) -12 = 0

9r^2 - 24r + 16 -12r + 48 - 12 = 0

9r^2 - 36r + 52 = 0

x =( -b + √b^2 - 4ac )/2a

= (-(-36) + √(36^2 - 4×9×52))/2×9

= (36+√(1296 - 1872))/18

=( 36+√-576 )18

= (36+ 24i) /18

= 2+ (4i/3) or

x = ( -b - √b^2 - 4ac )/2a

= (-(-36) - √(36^2 - 4×9×52))/2×9

= (36 - √(1296 - 1872))/18

=( 36 - √-576 )/18

= (36 - 24i) /18

= 2 - (4i/3)

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