Question

3rd one. No useless answers

Answer 1

${\underline{\bf{\pink{Hola}}}}$

Given:-

AOE=40°
BOD=35°

To find:-

•AOC
•COF

${\boxed{AOC=BOD=35°}}$
[Vertically opposite angles]

FOB=AOE=40°
[Vertically opposite angle]

COF+COA+FOB=180° [Linear Pair]
COF+35°+40°=180°
COF+75°=180°
COF=180°-75°

${\boxed{COF=105°}}$

${\green{\bf{Bebrainly}}}$

Answer 2

Step-by-step explanation:

∠AOC and ∠DOB are vertically opposite angles

so ∠AOC= ∠DOB=35°

∠AOC = 35°

|||ly

∠AOE and ∠FOB are vertically opposite angles

⇒ ∠FOB = 40°

In the line CD

∠COF + ∠FOB + ∠BOD = 180°

⇒ ∠COF +40 + 35 = 180°

⇒ ∠COF = 105°

Answer

∠AOC = 35°

∠COF = 105°

hope this helps

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