Question

3rd. Pls show the sum

Answer 1

Thanks for asking
Hope it will help

Answer 2

Hey

HERE IS THE ANSWER

Given sides =x cm and (X+4) cm.

sum of areas of two squares =
${656cm}^{2}$
As we know the area of square
$= {side}^{2}sq.unit$
so A/q
${x}^{2} + ( {x + 4)}^{2} = 656 \\ {x}^{2} + {x}^{2} + 8x + 16 - 656 = 0 \\ {2x}^{2} + 8x - 640 = 0 \\ {x}^{2} + 20x - 16x - 320 = 0 \\ x(x + 20) - 16(x + 20) = 0 \\ x + 20 = 0 \: \: \: or \: \: \: x - 16 = 0 \\ x = - 20 \: or \: x = 16 \: hence \: x = 16 \\ since \: side \: cannot \: be \: negative \\ \\ x + 4 = 16 + 4 = 20 \\ therefore \: sides \: of \: the \: square \: are \: \: 16cm \: and \: 20cm$
Hope it helps to you.