Question

3rd question answer I want

Answer 1

we have 2 find area of path pqrs and nmlk.
as shaded path comes in 1 of any area it may be pqrs or nmlk...
so area of pqrs=2*30=60
area of nmlk=2*20=40
we see shaded comes in both of them.so we have to remove it from 1 any
final area=(pqrs_shaded)+nmkl
=(60-2*2)+40
=96