3rd term 34 6th term 67 . find the 125th term.
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EXPLANATION
GIVEN
T3 = 34
T6 = 67
FIND FIRST FIVE TERM OF SEQUENCE
T3 = a + 2d = 34 (1)
T6 = a + 5d = 67 (2)
From equation (1) and equation (2)
we get,
-3d = - 33
d = 11
put d = 11 in equation(1)
we get,
a + 22 = 34
a = 12
First fifth term of
=> first term = a = 12
=> second term = a + d = 12 + 11 = 23
=> third term = a + 2d = 12 + 2(11) = 34
=> fourth term = a + 3d = 12 + 3(11) = 45
=> fifth term = a + 4d = 12 + 4(11) = 56
=> these terms are,
12,23,34,45,56
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