3rd term is 12 and a7 24 the a10
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Answered by
1
Answer:
a3=12
a+2d=12. (1)
a7=24
a+6d=24. (2)
Subtract (1)&(2)
a+2d=12
a+6d=24
-4d=-12
d=3
put d=3 in equation (1)
a+2(3)=12
a=6
Therefore,
a10=a+9d
=6+9(3)
=6+27
=33
HOPE IT HELPS YOU
Answered by
0
a3=12
a+2d=12
a7=24
a+6d=24
Subtracting both equations
a+2d-a-6d=12-24
-4d=-12
d=3
a+2d=12
a=12-6=6
a10=a+9d=6+9×3=33
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