Question

3rd term of a gp is 27 and its 6th term is 729. find the product of it's first and 7th term

Answer 1

ar^2=27.....(1)
ar^5=729.....(2)
on dividing 1 by 2,we get
r^3=729/27
r^3=27
r=3put value of r=3. in(1)
a=27/9
a=3
now 7th term =ar^6
3×729=2187
now product of 7th term and 1st term=3×2187
6561


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