3rd term of an ap is 1/5 and 5th term of ap is 1/3 what is sum of first 15 terms
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Answer:
Step-by-step explanation:
last term = first term + (n-1)d
considering first 3 terms
1/5 = a + (3-1)d = a + 2d
a = 1/5 - 2d .................. equation 1
considering first 5 terms
1/3 = a + (5-1)d = a + 4d
a = 1/3 - 4d .................. equation 2
on comparing both equations
1/5 - 2d = 1/3 - 4d
1/5 - 1/3 = 2d - 4d
-2/15 = -2d
d = 1/15
a = 1/15
sum of first 15 terms
S(n) = n/2[2a+(n-1)d]
Sn = 15/2[2/15+14/15]
Sn = 15/2[16/15]
Sn = 8
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