3rd term of an ap is47and 9th term of an ap is 85then find 27th term
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Solution:
Given:
3rd term of an ap = a+2d =47
9th term of an ap = a+8d = 85
change the symbols
-6d = -38
d= 38/6
d = 19/3
Now put d = 19/3 put in a+2d=47
a+2(19/3)=47
a+(38/3)=47
a=47-38/3
a= 9/3
a=3
Now we have both a and d
27th term = a+26d
3+26(19/3)
27th term=255.
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