3rooot of 15 or 4 root of 24which is greater
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∛15=(15)¹/³=(15)¹/³ˣ⁴/⁴ = (15)⁴/¹²=![\sqrt[12]{15^{4} }](https://tex.z-dn.net/?f=+%5Csqrt%5B12%5D%7B15%5E%7B4%7D+%7D+ "\sqrt[12]{15^{4} }")
= ![\sqrt[12]{50625}](https://tex.z-dn.net/?f=+%5Csqrt%5B12%5D%7B50625%7D+ "\sqrt[12]{50625}")
![\sqrt[4]{24}](https://tex.z-dn.net/?f=+%5Csqrt%5B4%5D%7B24%7D+ "\sqrt[4]{24}")
=(24)¹/⁴=(24)¹/⁴ˣ³/³=(24)³/¹²=![\sqrt[12]{ 24^{3} }](https://tex.z-dn.net/?f=+%5Csqrt%5B12%5D%7B+24%5E%7B3%7D+%7D+ "\sqrt[12]{ 24^{3} }")
=![\sqrt[12]{13824}](https://tex.z-dn.net/?f=+%5Csqrt%5B12%5D%7B13824%7D+ "\sqrt[12]{13824}")
∴,∛15
∴,∛15
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