Math, asked by Mukesh1329, 10 months ago

(3root 2-2root 3 / 3root 2+2 root 3)+(3 root 2+2 root 3/3 root 2-2 root 3 )simplyfy

Answers

Answered by dimprajapati
8

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Answered by rajivrtp
3

Answer:

10

Step-by-step explanation:

(3√2-2√3) / (3√2+2√3) + (3√2+2√3) / (3√2-2√3)

= (3√2-2√3)²/(18-12) + (3√2+2√3)² /(18-12)

(on rationalizing the denominator)

= [(3√2-2√3)²+(3√2+2√3)²] / 6

= (18+12-12√6+18+12+12√6) / 6

= 60 / 6

= 10

Hope this helps you

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