Question

3root 2+4root2-5root3

Answer 1

Answer:

Secondary School Math 13 points

Rationalise 4 root 3 +5root2/4 root 3+3 root 2

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Answer:

The rationalization of \frac{4\sqrt{3}+5\sqrt{2}}{4\sqrt{3}+3\sqrt{2}} is \frac{9+4\sqrt{6}}{15}

Step-by-step explanation:

Given : 4 root 3 +5 root 2/4 root 3+3 root 2

To find : Rationalize the given expression?

Solution :

The given expression is \frac{4\sqrt{3}+5\sqrt{2}}{4\sqrt{3}+3\sqrt{2}}

Rationalizing the expression by multiplying and dividing denominator with opposite sign,

=\frac{4\sqrt{3}+5\sqrt{2}}{4\sqrt{3}+3\sqrt{2}}\times \frac{4\sqrt{3}-3\sqrt{2}}{4\sqrt{3}-3\sqrt{2}}

The denominator is multiplied by using the formula,

\bold{(a+b)(a-b)=a^{2}-b^{2}}

=\frac{(4\sqrt{3})^2-(4\sqrt{3})(3\sqrt2)+(5\sqrt{2})(4\sqrt{3})-(5\sqrt{2})(3\sqrt{2})}{(4\sqrt{3})^2-(3\sqrt{2})^2}

=\frac{48-12\sqrt{6}+20\sqrt{6}-30}{48-18}

=\frac{9+4\sqrt{6}}{15}

Therefore, The rationalization of \frac{4\sqrt{3}+5\sqrt{2}}{4\sqrt{3}+3\sqrt{2}} is \frac{9+4\sqrt{6}}{15}

Answer 2

Answer:

7√2-5√3 add me in brainlist