Question

3root 8 multiply by 3 root 2

Answer 1

Step-by-step explanation:

Given question is$\rm (3\sqrt 8)\times (3\sqrt 2)\\ \\ \rm \implies (9\times \sqrt{16}\\ \\ \rm \implies 36\qquad \qquad (\because \sqrt{16}=4)\\ \\ \bf \therefore The\ value\ of\ 3\sqrt8\ \times\ 3\sqrt2\ is\ 36.$

Know more:-

◆ Here a irrational number is multiplied by another irrational number, so it shows that multiplication of two irrationals is rational.

◆ Sum of two irrationals is irrational.

◆ Subtraction of two irrationals is rational or irrational.

◆ Division of two irrationals is rational or irrational.

Answer 2

$\huge\mathbb\pink{Answer}$

$3 \sqrt{8} \times 3 \sqrt{2}$

$= (3 \times 3) \times ( \sqrt{8 \times 2} )$

$= 9 \times \sqrt{16}$

$= 9 \times 4$

$= 36$