Question

3root2 -2 root 3 /root 8 +root 27​

Answer 1

Step-by-step explanation:

$\frac{3 \sqrt{2} - 2 \sqrt{3} }{ \sqrt{8} + \sqrt{27} } = > \frac{3 \sqrt{2} - 2 \sqrt{3} }{2 \sqrt{2} + 3 \sqrt{3} } = >$

$\frac{(3 \sqrt{2} - 2 \sqrt{3})(3 \sqrt{3} - 2 \sqrt{2})}{(3 \sqrt{3} - 2 \sqrt{2})(3 \sqrt{3} + 2 \sqrt{2})} = > \frac{9 \sqrt{6} - 12 -18 + 6 \sqrt{6} }{(27 - 8)}$

$= > \frac{15 \sqrt{6} - 30}{19}$

Hope it helps you.