Question

3root2 ,3root7 ,6root5 ,2root5 Which number is greater

Answer 1

Answer:

The answer is $6\sqrt 5$

Step-by-step explanation:

$3\sqrt 2=\sqrt{3^2\times 2}=\sqrt{18}\\3\sqrt 7=\sqrt{3^2\times 7}=\sqrt{63}\\6\sqrt 5=\sqrt{6^2\times 5}=\sqrt{180}\\2\sqrt 5=\sqrt{2^2\times 5}=\sqrt{20}$

Clearly $6\sqrt 5=\sqrt{180}$ is greater