Question

3root48 - 5/2root1/3 + 4root3

Answer 1

$Let \: a \: = 3 \sqrt{48 } - \frac{5}{2} \sqrt{ \frac{1}{3} } + 4 \sqrt{3}$

$\\ = 12 \sqrt{3} - \frac{5}{2 \sqrt{3} } + 4 \sqrt{3}$

$\\ = \frac{72 - 5 + 24}{2 \sqrt{3} }$

$\\ a = \frac{91}{2 \sqrt{3} }$

$\\ ∴3 \sqrt{48} - \frac{5}{2} \sqrt{ \frac{1}{3} } + 4 \sqrt{3} = \frac{91}{2 \sqrt{3} }$

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