3root5-root7/3root3+root2
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Answered by
18
Hi ,
( 3√5 - √7 )/(3√3 + √2 )
=[(3√5-√7)(3√3-√2)]/[(3√3+√2)(3√3-√2)]
=[9√15-3√10-3√21+√14]/[(3√3)²-(√2)²]
=[-3√10+√14+9√15-3√21]/(27-2)
= (-3√10+√14+9√15-3√21)/25
I hope this helps you.
; )
( 3√5 - √7 )/(3√3 + √2 )
=[(3√5-√7)(3√3-√2)]/[(3√3+√2)(3√3-√2)]
=[9√15-3√10-3√21+√14]/[(3√3)²-(√2)²]
=[-3√10+√14+9√15-3√21]/(27-2)
= (-3√10+√14+9√15-3√21)/25
I hope this helps you.
; )
kittu40:
thanks
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Hi,
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