Question

3sec+inverse1/x-sin+inverse(4x^3-3x)+=3/2

Answer 1

Answer:

Step-by-step explanation:

Let x=sinθ⇒sin  

−1

x=θ.

Thus we have,  

R.H.S.=sin  

−1

(3x−4x  

3

)=sin  

−1

(3sinθ−4sin  

3

θ)

               =sin  

−1

(sin3θ)=3θ=3sin  

−1

x

               =L.H.S.