Question

3sin⁻¹ 1/2+ 4cos⁻¹ √3/2+ sec⁻¹ 1, Find value of it.

Answer 1

we have to find the value of 3sin⁻¹ 1/2+ 4cos⁻¹ √3/2+ sec⁻¹ 1

we know,

• sin(π/6) = 1/2 ⇒sin-¹(1/2) = π/6
• cos(π/6) = √3/2 ⇒cos-¹(√3/2) = π/6
• sec(0) = 1 ⇒sec-¹(1) = 0

now, 3sin⁻¹ 1/2+ 4cos⁻¹ √3/2+ sec⁻¹ 1

= 3 × (π/6) + 4(π/6) + 0

= 3π/6 + 4π/6

= (3π + 4π)/6

= 7π/6

hence, 3sin⁻¹ 1/2+ 4cos⁻¹ √3/2+ sec⁻¹ 1 = 7π/6

also read :

sec⁻¹(cosec(π/8)), Evaluate it.

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