Question

3sin^4x + cos^4x=1 find the solution set

Answer 1

this questionis incomplete

Answer 2

Answer: x = nπ ∪ nπ ± $\frac{\pi }{4}$

Step-by-step explanation:

$3sin^{4} x + cos^{4} x =1$

$3sin^{4}x = 1 - cos^{4} x$

$3sin^{4}x = (1 - cos^{2} x)(1+cos^{2} x)$

$3sin^{4} x= sin^{2} x (1 + cos^{2} x )$

$sin^{2}x (3sin^{2} x -1-cos^2x)$ = 0

$sin^2x(3sin^2x-1-1+sin^2x) = 0$

sin²x = 0    ,  sin²x = 1/2

x = nπ ,  x = nπ ± $\frac{\pi }{4}$

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