Question

3sin 60degree-4sincube60degree

Answer 1

Answer:

Step-by-step explanation:

Answer 2

Step-by-step explanation:

$= > sin60 \degree= \frac{ \sqrt{3} }{2} \\ \\ we \: will \: find \: to \: this \: equation \\ \\ = > 3sin60 \degree - 4 {sin}^{3} 60 \degree \\ \\ \: \: \: put \: value \: in \: equation \: of \: sin60 \degree \\ \\ = > 3( \frac{ \sqrt{3} }{2} ) - 4( { \frac{ \sqrt{3} }{2} })^{3} \\ \\ = > \frac{3 \sqrt{3} }{2} - 4 \times \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} \times \frac{ \sqrt{3} }{2} \\ \\ = > \frac{3 \sqrt{3} }{2} - 4 \times \frac{3 \sqrt{3} }{8} \\ \\ = > \frac{3 \sqrt{ 3} }{2} - \frac{3 \sqrt{3} }{2} \\ \\ = > 0$