Question

(3sin A . sec A + 2cos A . sin A) by sin A .cos A

Answer 1

Answer:

2

Step-by-step explanation:

Assume A = 45

3 Sin A = 3(1/√2)

Sec A = √2

2 cos A = 2(1/√2)

Sin A = 1/√2

Cos A = 1/√2

Therefore,

[ 3(1/√2) × √2 + 2(1/√2)(1/√2) ] ÷ 1/√2 × 1/√2

( 3 + 1 ) ÷ 1/2

4/2 = 2.

Therefore 2 is ur answer!