3sin theta=1 than the value ofcos theta
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Given 3 sin theta =1
So; sin theta =1/3 = opp/ hyp
By Pythagoras theorem
AC^2= AB^2 +BC^2
3^2=1^2+BC^2
9 = 1+BC^2
BC^2 = 9-1
BC = √8
So cos theta = adj / hyp
= √8/3
Therefore cos theta =√8/3
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